330. a) The sum of the roots of the equation of degree n
xn−C2n+11C2n+13xn−1+C2n+11C2n+15xn−2−…=0
(see the solution of problem 229 b)) is equal to the coefficient of xn−1, taken with the opposite sign, i.e.
ctg22n+1π+ctg22n+12π+ctg22n+13π+…+ctg22n+1nπ=
=C2n+11C2n+13=3n(2n−1)
b) Since cosec2α=ctg2α+1, it follows from the formula of problem a) that
cosec22n+1π+cosec22n+12π+cosec22n+13π+…
…+cosec22n+1nπ=3n(2n−1)+n=32n(n+1)