33.1. A six-digit number starts with one. If this one is moved to the end of the number, the resulting number will be three times the given number. Find the given number.
(7-10 grades)
A number or a short expression. Spacing, $ signs and \frac vs / are all fine.
Official solution
33.1. The desired six-digit number has the form 1abcde. According to the problem, 3⋅1abcde=abcde1 or 3(100000+abcde)=1+10⋅abcde. From this, 7⋅abcde=299999, i.e., abcde=42857. Therefore, the desired number is 142857.
Source: NuminaMath-1.5,
licensed Apache-2.0.
Statement and solution reproduced as published; topic, difficulty and ordering added
by this site.