Maths Olympiad Prep

Track / Stage 4 / 122 of 340 #382 of 1964

Problem 382

AMC 12 late, AIME early
Algebra Difficulty 4.8 Find the answer

2. Given (a+bi)2=3+4i(a+b i)^{2}=3+4 i, where a,bR,ia, b \in \mathbf{R}, i is the imaginary unit, then the value of a2+b2a^{2}+b^{2} is \qquad

A number or a short expression. Spacing, $ signs and \frac vs / are all fine.

Official solution

Answer 5.
Analysis From (a+bi)2=3+4i(a+b i)^{2}=3+4 i we get a+bi2=3+4i|a+b i|^{2}=|3+4 i|, which means a2+b2=5a^{2}+b^{2}=5.

Source: NuminaMath-1.5, licensed Apache-2.0. Statement and solution reproduced as published; topic, difficulty and ordering added by this site.