1. Define the set and its properties:
Let A={x1,x2,x3,x4,x5} be a set of five distinct positive integers. Denote by SA the sum of its elements:
SA=x1+x2+x3+x4+x5
Denote by TA the number of triples (i,j,k) with 1≤i<j<k≤5 for which xi+xj+xk divides SA.
2. Calculate the number of possible triples:
The number of ways to choose 3 elements out of 5 is given by the binomial coefficient:
(35)=10
Therefore, there are 10 possible triples (i,j,k).
3. Example with specific values:
Consider the set A={1,2,3,4,494}:
SA=1+2+3+4+494=504
We need to check which triples (i,j,k) satisfy the condition that xi+xj+xk divides SA.
4. Check each triple:
- For (1,2,3):
x1+x2+x3=1+2+3=6and504÷6=84(divides)
- For (1,2,4):
x1+x2+x4=1+2+4=7and504÷7=72(divides)
- For (1,2,5):
x1+x2+x5=1+2+494=497and504÷497(does not divide)
- For (1,3,4):
x1+x3+x4=1+3+4=8and504÷8=63(divides)
- For (1,3,5):
x1+x3+x5=1+3+494=498and504÷498(does not divide)
- For (1,4,5):
x1+x4+x5=1+4+494=499and504÷499(does not divide)
- For (2,3,4):
x2+x3+x4=2+3+4=9and504÷9=56(divides)
- For (2,3,5):
x2+x3+x5=2+3+494=499and504÷499(does not divide)
- For (2,4,5):
x2+x4+x5=2+4+494=500and504÷500(does not divide)
- For (3,4,5):
x3+x4+x5=3+4+494=501and504÷501(does not divide)
5. Count the valid triples:
The valid triples are (1,2,3), (1,2,4), (1,3,4), and (2,3,4). Thus, there are 4 valid triples.
Conclusion:
4