Olympiad Maths Prep

Track / Stage 3 / 156 of 260 #156 of 2000

Problem 156

AMC 10/12, early questions
Number theory Difficulty 3.7 Find the answer

Call a positive real number special if it has a decimal representation that consists entirely of digits 00 and 77. For example, 70099=7.07=7.070707\frac{700}{99}= 7.\overline{07}= 7.070707\cdots and 77.00777.007 are special numbers. What is the smallest nn such that 11 can be written as a sum of nn special numbers?
(A) 7(B) 8(C) 9(D) 10(E) The number 1 cannot be represented as a sum of finitely many special numbers.\textbf{(A)}\ 7\qquad\textbf{(B)}\ 8\qquad\textbf{(C)}\ 9\qquad\textbf{(D)}\ 10\qquad\\ \textbf{(E)}\ \text{The number 1 cannot be represented as a sum of finitely many special numbers.}

Official solution

Define a super-special number to be a number whose decimal expansion only consists of 00's and 11's. The problem is equivalent to finding the number of super-special numbers necessary to add up to 17=0.142857142857\hdots\frac{1}{7}=0.142857142857\hdots. This can be done in 88 numbers if we take
0.111111\hdots,0.011111\hdots,0.010111\hdots,0.010111\hdots,0.000111\hdots,0.000101\hdots,0.000101\hdots,0.000100\hdots0.111111\hdots, 0.011111\hdots, 0.010111\hdots, 0.010111\hdots, 0.000111\hdots, 0.000101\hdots, 0.000101\hdots, 0.000100\hdots
Now assume for sake of contradiction that we can do this with strictly less than 88 super-special numbers (in particular, less than 1010.) Then the result of the addition won't have any carry over, so each digit is simply the number of super-special numbers which had a 11 in that place. This means that in order to obtain the 88 in 0.1428\hdots0.1428\hdots, there must be 88 super-special numbers, so the answer is (B) 8\boxed{\textbf{(B)}\ 8}.

Source: NuminaMath-1.5, licensed Apache-2.0. Statement and solution reproduced as published; topic, difficulty and ordering added by this site.