1. Let a,b be integers, a⩾1,b=qa+r,0⩽r<a. Prove: q=[b/a],r=a{b/a}.
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Official solution
1. b/a=[b/a]+{b/a},b=[b/a]a+{b/a}a, This gives a new proof of the division algorithm (Theorem 1, §3).
Source: NuminaMath-1.5,
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