Olympiad Maths Prep

Track / Stage 5 / 41 of 400 #641 of 2000

Problem 641

AIME late
Algebra Difficulty 5.1 Find the answer

5. The line y=kx2y=k x-2 intersects the parabola y2=8xy^{2}=8 x at points A,BA, B. If the x-coordinate of the midpoint of segment ABA B is 2, then the length of segment ABA B AB=|A B|= \qquad

Official solution

{y=kx2,y2=8xk2x2(4k+8)x+4=0x0=2k+4k2=2k2=k+2 \left\{\begin{array}{l} y=k x-2, \\ y^{2}=8 x \end{array} \Rightarrow k^{2} x^{2}-(4 k+8) x+4=0 \Rightarrow x_{0}=\frac{2 k+4}{k^{2}}=2 \Rightarrow k^{2}=k+2\right.
k=2x24x+1=0\Rightarrow k=2 \Rightarrow x^{2}-4 x+1=0. So AB=5164=215|A B|=\sqrt{5} \cdot \sqrt{16-4}=2 \sqrt{15}.

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