Olympiad Maths Prep

Track / Stage 4 / 334 of 340 #594 of 2000

Problem 594

AMC 12 late, AIME early
Geometry Difficulty 5.0 Find the answer

10. Five identical right-angled triangles can be arranged so that their larger acute angles touch to form the star shown in the diagram. It is also possible to form a different star by arranging more of these triangles so that their smaller acute angles touch.
How many triangles are needed to form the second star?

A 10
B 12
C 18
D 20
E 24

Official solution

SolUtion
D

Since the five identical triangles meet at a point, the size of the larger acute angle in each triangle is 360÷5=72360^{\circ} \div 5=72^{\circ}. Therefore the smaller acute angle in each triangle is 1809072=18180^{\circ}-90^{\circ}-72^{\circ}=18^{\circ}. Hence, since the second star is formed using the triangles whose smaller acute angles touch, the number of triangles needed to form the second star is 360÷18=20360 \div 18=20.

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