Maths Olympiad Prep

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Problem 505

AMC 10/12, early questions
Geometry Difficulty 3.1 Find the answer CEMC Fermat

Aaron has 144 identical cubes, each with edge length 1 cm. He uses all of the cubes to construct a solid rectangular prism, which he places on a flat table. If the perimeter of the base of the prism is 20 cm, what is the sum of all possible heights of the prism?

A number or a short expression. Fractions can be typed as 3/2, and spacing doesn't matter.

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Official solution

Suppose that the base of the prism is b cmb \mathrm{~cm} by w cmw \mathrm{~cm} and the height of the prism is h cmh \mathrm{~cm}. Since Aaron has 144 cubes with edge length 1 cm, then the volume of the prism is 144 cm3144 \mathrm{~cm}^{3}, and so bwh=144bwh = 144. Since the perimeter of the base is 20 cm, then 2b+2w=202b + 2w = 20 or b+w=10b + w = 10. Since bb and ww are positive integers, then we can make a chart of the possible combinations of bb and ww and the resulting values of h=144bwh = \frac{144}{bw}, noting that since bb and ww are symmetric, then we can assume that bwb \leq w:

bwh1916289374874665514425\begin{array}{c|c|c} b & w & h \\ \hline 1 & 9 & 16 \\ 2 & 8 & 9 \\ 3 & 7 & \frac{48}{7} \\ 4 & 6 & 6 \\ 5 & 5 & \frac{144}{25} \end{array}

Since hh must itself be a positive integer, then the possible values of hh are 16, 9, and 6. The sum of the possible heights is 16 cm+9 cm+6 cm=31 cm16 \mathrm{~cm} + 9 \mathrm{~cm} + 6 \mathrm{~cm} = 31 \mathrm{~cm}.

Source: Omni-MATH, licensed Apache-2.0. Statement reproduced verbatim; metadata (topic, difficulty, ordering) added by this project.