Maths Olympiad Prep

Track / Stage 5 / 62 of 400 #1142 of 2444

Problem 1142

AIME late
Geometry Difficulty 5.1 Find the answer HMMT February

A semicircle with radius 2021 has diameter ABAB and center OO. Points CC and DD lie on the semicircle such that AOC<AOD=90\angle AOC < \angle AOD = 90^{\circ}. A circle of radius rr is inscribed in the sector bounded by OAOA and OCOC and is tangent to the semicircle at EE. If CD=CECD=CE, compute r\lfloor r \rfloor.

A number or a short expression. Fractions can be typed as 3/2, and spacing doesn't matter.

Next problem →

Official solution

We are given mEOC=mCODm \angle EOC = m \angle COD and mAOC+mCOD=2mEOC+mCOD=90m \angle AOC + m \angle COD = 2m \angle EOC + m \angle COD = 90^{\circ} So mEOC=30m \angle EOC = 30^{\circ} and mAOC=60m \angle AOC = 60^{\circ}. Letting the radius of the semicircle be RR, we have (Rr)sinAOC=rr=13R(R-r) \sin \angle AOC = r \Rightarrow r = \frac{1}{3} R so r=20213=673\lfloor r \rfloor = \left\lfloor\frac{2021}{3}\right\rfloor = 673

Source: Omni-MATH, licensed Apache-2.0. Statement reproduced verbatim; metadata (topic, difficulty, ordering) added by this project.