We apply DeMoivre's Theorem to simplify the first expression to (cos6⋅32π+sin6⋅32π)=(cos4π+sin4π)=1+0=1. Similarly, we simplify the second expression to (cos6⋅34π+sin6⋅34π)=(cos8π+sin8π)=1+0=1. Thus, the total sum is 1+1=2.
Source: Omni-MATH,
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