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Problem 1138

AMC 12 late, AIME early

Algebra Difficulty 4.8 Find the answer HMMT November

Compute $\frac{x}{w}$ if $w \neq 0$ and $\frac{x+6 y-3 z}{-3 x+4 w}=\frac{-2 y+z}{x-w}=\frac{2}{3}$ .

Your answer

A number or a short expression. Fractions can be typed as 3/2, and spacing doesn't matter.

Official solution

We have $x+6 y-3 z=\frac{2}{3}(-3 x+4 w)$ and $-2 y+z=\frac{2}{3}(x-w)$ , so $\frac{x}{w}=\frac{(x+6 y-3 z)+3(-2 y+z)}{(-3 x+4 w)+3(x-w)}=\frac{\frac{2}{3}(-3 x+4 w)+3 \cdot \frac{2}{3}(x-w)}{(-3 x+4 w)+3(x-w)}=\frac{\frac{2}{3}[(-3 x+4 w)+3(x-w)]}{(-3 x+4 w)+3(x-w)}=\frac{2}{3}$

Source: Omni-MATH, licensed Apache-2.0. Statement reproduced verbatim; metadata (topic, difficulty, ordering) added by this project.