Maths Olympiad Prep

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Stage 7 · Mixed

10 problems · National Olympiad second round; IMO P1/P4 · mathsolympiadprep.com

The answer key prints on its own page at the end.

  1. Find all integers n≥3n \geq 3 such that the following property holds: if we list the divisors of n !n ! in increasing order as 1=d1<d2<⋯<dk=n!1=d_1<d_2<\cdots<d_k=n! , then we have d2−d1≤d3−d2≤⋯≤dk−dk−1.d_2-d_1 \leq d_3-d_2 \leq \cdots \leq d_k-d_{k-1} .
    Contents 1 Solution (Explanation of Video) 2 Solution 2 3 Video Solution 4

    USAMO

    Number theory Solution and answer checking →

  2. Let a1,a2,⋯ ,ana_1,a_2,\cdots,a_n be a permutation of 1,2,⋯ ,n1,2,\cdots,n. Among all possible permutations, find the minimum of ∑i=1nmin⁡{ai,2i−1}.\sum_{i=1}^n \min \{ a_i,2i-1 \}.

    China Team Selection Test

    Algebra Solution and answer checking →

  3. Find all triples of positive integers (x,y,z)(x,y,z) that satisfy the equation
    2(x+y+z+2xyz)2=(2xy+2yz+2zx+1)2+2023.2(x+y+z+2xyz)^2=(2xy+2yz+2zx+1)^2+2023.

    USAJMO

    Algebra Solution and answer checking →

  4. Find all pairs (p,q)(p,q) of prime numbers which p>qp>q and
    (p+q)p+q(p−q)p−q−1(p+q)p−q(p−q)p+q−1\frac{(p+q)^{p+q}(p-q)^{p-q}-1}{(p+q)^{p-q}(p-q)^{p+q}-1}
    is an integer.

    IMO Shortlist

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  5. Let a1,a2,⋯ ,a41∈R,a_1,a_2,\cdots,a_{41}\in\mathbb{R}, such that a41=a1,∑i=140ai=0,a_{41}=a_1, \sum_{i=1}^{40}a_i=0, and for any i=1,2,⋯ ,40,∣ai−ai+1∣≤1.i=1,2,\cdots,40, |a_i-a_{i+1}|\leq 1. Determine the greatest possible value of
    (1)a10+a20+a30+a40;(1)a_{10}+a_{20}+a_{30}+a_{40};
    (2)a10⋅a20+a30⋅a40.(2)a_{10}\cdot a_{20}+a_{30}\cdot a_{40}.

    China National Olympiad

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  6. For which positive integers mm does there exist an infinite arithmetic sequence of integers a1,a2,...a_1, a_2, . . . and an infinite geometric sequence of integers g1,g2,...g_1, g_2, . . . satisfying the following properties?

    - an−gna_n - g_n is divisible by mm for all integers n≥1n \ge 1;

    - a2−a1a_2 - a_1 is not divisible by mm.

    Holden Mui

    USAJMO

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  7. Find the smallest positive integer nn such that if nn squares of a 1000×10001000 \times 1000 chessboard are colored, then there will exist three colored squares whose centers form a right triangle with sides parallel to the edges of the board.

    USAMO

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  8. Given a acute triangle PA1B1PA_1B_1 is inscribed in the circle Γ\Gamma with radius 11. for all integers n≥1n \ge 1 are defined:
    CnC_n the foot of the perpendicular from PP to AnBnA_nB_n
    OnO_n is the center of ⊙(PAnBn)\odot (PA_nB_n)
    An+1A_{n+1} is the foot of the perpendicular from CnC_n to PAnPA_n
    Bn+1≡PBn∩OnAn+1B_{n+1} \equiv PB_n \cap O_nA_{n+1}

    If PC1=2PC_1 =\sqrt{2}, find the length of PO2015PO_{2015}

    Cono Sur Olympiad - 2015 - Day 1 - Problem 3

    Cono Sur Olympiad

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  9. Let n>5n>5 be an integer. There are nn points in the plane, no three of them collinear. Each day, Tom erases one of the points, until there are three points left. On the ii-th day, for 1<i<n−31<i<n-3, before erasing that day's point, Tom writes down the positive integer v(i)v(i) such that the convex hull of the points at that moment has v(i)v(i) vertices. Finally, he writes down v(n−2)=3v(n-2) = 3. Find the greatest possible value that the expression
    ∣v(1)−v(2)∣+∣v(2)−v(3)∣+…+∣v(n−3)−v(n−2)∣|v(1)-v(2)|+ |v(2)-v(3)| + \ldots + |v(n-3)-v(n-2)|
    can obtain among all possible initial configurations of nn points and all possible Tom's moves.

    European Mathematical Cup

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  10. Find all positive integers n,k1,…,knn, k_1, \dots, k_n such that k1+⋯+kn=5n−4k_1 + \cdots + k_n = 5n-4 and 1k1+⋯+1kn=1. \frac{1}{k_1} + \cdots + \frac{1}{k_n} = 1.

    Putnam

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Answer key — Stage 7 · Mixed

Worked solutions for every problem are on the site, one page per problem.

  1. The integers n≥3 n \geq 3 that satisfy the given property are n=3 n = 3 and n=4 n = 4 . open
  2. ∑i=1nmin⁡{n+1−i,2i−1}\sum_{i=1}^n \min \{ n + 1 - i, 2i-1 \} open
  3. (2,3,3)(2, 3, 3) open
  4. (3,2)(3, 2) open
  5. 1010 open
  6. m is not squarefree\text{m is not squarefree} open
  7. 1999\boxed{1999} open
  8. 121007\frac{1}{2^{1007}} open
  9. 2n−82n - 8 open
  10. n=1,k1=1;n=3,(k1,k2,k3)=(2,3,6);n=4,(k1,k2,k3,k4)=(4,4,4,4)n = 1, k_1 = 1; n = 3, (k_1,k_2,k_3) = (2,3,6); n = 4, (k_1,k_2,k_3,k_4) = (4,4,4,4) open

Problems belong to the competitions that set them. Each question on this sheet names the competition it came from, and the licences the material is used under are listed below. Free to copy for classroom use.

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