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Stage 8 · Geometry

10 problems · IMO Shortlist mid-range; USAMO P2/P5 · mathsolympiadprep.com

The answer key prints on its own page at the end.

  1. Points AA, V1V_1, V2V_2, BB, U2U_2, U1U_1 lie fixed on a circle Γ\Gamma, in that order, and such that BU2>AU1>BV2>AV1BU_2 > AU_1 > BV_2 > AV_1.

    Let XX be a variable point on the arc V1V2V_1 V_2 of Γ\Gamma not containing AA or BB. Line XAXA meets line U1V1U_1 V_1 at CC, while line XBXB meets line U2V2U_2 V_2 at DD. Let OO and ρ\rho denote the circumcenter and circumradius of △XCD\triangle XCD, respectively.

    Prove there exists a fixed point KK and a real number cc, independent of XX, for which OK2−ρ2=cOK^2 - \rho^2 = c always holds regardless of the choice of XX.

    USA Team Selection Test

    Geometry Solution and answer checking →

  2. Given positive integer n≥5 n \ge 5 and a convex polygon PP, namely A1A2...An A_1A_2...A_n . No diagonals of PP are concurrent. Proof that it is possible to choose a point inside every quadrilateral AiAjAkAl(1≤i<j<k<l≤n) A_iA_jA_kA_l (1\le i<j<k<l\le n) not on diagonals of PP, such that the (n4) \tbinom{n}{4} points chosen are distinct, and any segment connecting these points intersect with some diagonal of P.

    China Team Selection Test

    Geometry Solution and answer checking →

  3. Let ABCABC be an acute triangle. Let DAC,EABDAC,EAB, and FBCFBC be isosceles triangles exterior to ABCABC, with DA=DC,EA=EBDA=DC, EA=EB, and FB=FCFB=FC, such that
    ∠ADC=2∠BAC,∠BEA=2∠ABC,∠CFB=2∠ACB. \angle ADC = 2\angle BAC, \quad \angle BEA= 2 \angle ABC, \quad \angle CFB = 2 \angle ACB.
    Let D′D' be the intersection of lines DBDB and EFEF, let E′E' be the intersection of ECEC and DFDF, and let F′F' be the intersection of FAFA and DEDE. Find, with proof, the value of the sum
    DBDD′+ECEE′+FAFF′. \frac{DB}{DD'}+\frac{EC}{EE'}+\frac{FA}{FF'}.

    IMO Shortlist

    Geometry Solution and answer checking →

  4. There is given a convex quadrilateral ABCDABCD and a point PP in the interior of the triangle BCDBCD in such a way that the quadrilateral ABPDABPD has an inscribed circle, and the three inscribed circles of the quadrilateral ABPDABPD, the triangle BCPBCP and the triangle CDPCDP, respectively, are pairwise tangent to each other. Denote by QQ and RR the points tangency on the line segments BPBP and DPDP, respectively. Let the lines BPBP and ARAR meet at SS, let the lines DPDP and AQAQ meet at TT, and let the lines BTBT and DSDS meet at UU. Show that the line CUCU bisects the angle BCDBCD.
    (5 pont)

    KöMaL problem A 2015

    Geometry Solution and answer checking →

  5. Triangle ABCABC has incenter II and excircles ΩA\Omega_A, ΩB\Omega_B, and ΩC\Omega_C. Let ℓA\ell_A be the line through the feet of the tangents from II to ΩA\Omega_A, and define lines ℓB\ell_B and ℓC\ell_C similarly. Prove that the orthocenter of the triangle formed by lines ℓA\ell_A, ℓB\ell_B, and ℓC\ell_C coincides with the Nagel point of triangle ABCABC.

    KöMaL problem A 2022

    Geometry Solution and answer checking →

  6. In triangle ABCABC, we have AB>ACAB > AC. The incircle ω\omega touches BCBC at EE, and AEAE intersects ω\omega at DD. Choose a point FF on AEAE (FF is different from EE), such that CE=CFCE = CF. Let GG be the intersection point of CFCF and BDBD. Prove that CF=FGCF = FG.

    China National Team Selection Test

    Geometry Solution and answer checking →

  7. Let ABCABC be an acute-angled triangle with circumcenter OO. Furthermore, let kk be a circle with the following properties:

    (1) The center KK of kk lies in the interior of the side BCBC.

    (2) kk touches ABAB at B′B' and ACAC at C′C'.

    (3) OO lies on the shorter of the two arcs B′C′B'C' of kk.

    Prove: The circumcircle of ABCABC and kk intersect each other in two distinct points.

    Auswahlklausur

    Geometry Solution and answer checking →

  8. Let ABCDABCD be a trapezium inscribed in a circle kk with diameter ABAB. A circle with center BB and radius BEBE, where EE is the intersection point of the diagonals ACAC and BDBD meets kk at points KK and LL. If the line, perpendicular to BDBD at EE, intersects CDCD at MM, prove that KM⊥DLKM \perp DL.

    Balkan Mathematical Olympiad Shortlist

    Geometry Solution and answer checking →

  9. Let PP be a point inside the triangle ABCABC satisfying ∠PAC=∠PCB\angle PAC = \angle PCB and DD be the midpoint of the line segment PCPC. Let APAP intersect BCBC at EE and EDED intersect BPBP at QQ such that PP is on the line segment BQBQ. Prove that ∠BAP+∠BCQ=180∘\angle BAP + \angle BCQ = 180^\circ.

    Turkey — Team Selection Test

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  10. Let ABCABC be an isosceles triangle, AB=ACAB = AC, and let MM and NN be points on the sides BCBC and CACA, respectively, such that the angles BAMBAM and CNMCNM are equal. The lines ABAB and MNMN meet at PP. Show that the internal angle bisectors of the angles BAMBAM and BPMBPM meet at a point on the line BCBC.

    Bogdan Enescu

    Figure 1

    NMO Selection Tests for BMO and IMO

    Geometry Solution and answer checking →

Answer key — Stage 8 · Geometry

Worked solutions for every problem are on the site, one page per problem.

  1. K is the intersection of AB′ and BA′, and c is a constantK \text{ is the intersection of } AB' \text{ and } BA', \text{ and } c \text{ is a constant} open
  2. Proven\text{Proven} open
  3. 44 open
  4. Prove it — see the worked solution open
  5. Prove it — see the worked solution open
  6. Prove it — see the worked solution open
  7. Prove it — see the worked solution open
  8. Prove it — see the worked solution open
  9. Prove it — see the worked solution open
  10. Prove it — see the worked solution open

Problems belong to the competitions that set them. Each question on this sheet names the competition it came from, and the licences the material is used under are listed below. Free to copy for classroom use.

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