Maths Olympiad Prep

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Combinatorics Difficulty 4.8 AIME Find the answer Canada

A die is created with the integers 11, 22, 22, 44, 77, 88
on its six faces. The first time the die is rolled, the numbers on its
faces are changed in the following way:

If the number rolled is odd, then all odd numbers on the die are
doubled, and all even numbers remain the same.
If the number rolled is even, then all even numbers on the die
are halved, and all odd numbers remain the same.

The die is then rolled a second time. What is the probability that
the second number rolled is 22?

Pick one

Solution

The probability that the second roll is a 22 is equal to the probability that the
first roll is odd and the second roll is a 22, added to the probability that the
first roll is even and the second roll is a 22.

The original die has 22 odd numbers
and 44 even numbers on its faces.
Thus the probability that the first roll is odd is 26\dfrac26, and the probability that the
first roll is even is 46\dfrac46.

If the first roll is odd, the numbers on the faces are changed to
22, 22, 22, 44, 1414, 88.

In this case, the probability that the second roll is a 22 is 36\dfrac36, and so the probability that the
first roll is odd and the second roll is 22 is 26×36=636\dfrac26\times\dfrac36=\dfrac{6}{36}.

If the first roll is even, the numbers on the faces are changed to
11, 11, 11, 22, 77, 44.

In this case, the probability that the second roll is a 22 is 16\dfrac16, and so the probability that the
first roll is even and the second roll is 22 is 46×16=436\dfrac46\times\dfrac16=\dfrac{4}{36}.

Thus, the probability that the second roll is a 22 is equal to 636+436=1036=518\dfrac{6}{36}+\dfrac{4}{36}=\dfrac{10}{36}=\dfrac{5}{18}.

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Source: CEMC, University of Waterloo, licensed CC-BY-NC-4.0. Statement reproduced verbatim; metadata (topic, difficulty) added by this project.