Maths Olympiad Prep

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Algebra Difficulty 1.4 Junior Find the answer Canada

The number that goes into the \Box to make 37=63\dfrac{3}{7} = \dfrac{\Box}{63} true is

Pick one

Solution

The denominators of the two fractions are 7 and 63.

Since 7×9=637\times9=63, then we must also multiply the numerator 3 by 9 so that the fractions are equivalent.

That is, 37=3×97×9=2763\dfrac37=\dfrac{3\times9}{7\times9}=\dfrac{27}{63}.

Therefore, the number that goes into the \Box so that the statement true is 27.

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Source: CEMC, University of Waterloo, licensed CC-BY-NC-4.0. Statement reproduced verbatim; metadata (topic, difficulty) added by this project.