Library / /14 of 387

, 1998

Algebra Difficulty 1.0 Junior Find the answer Canada

If $x+y+z=25$ , $x+y=19$ and $y+z=18$ , then $y$ equals

(A) $13$ (B) $17$ (C) $12$ (D) $6$ (E) $-6$

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Source: CEMC, University of Waterloo, licensed CC-BY-NC-4.0. Statement reproduced verbatim; metadata (topic, difficulty) added by this project. Solutions are the publisher's, linked not copied.