Maths Olympiad Prep

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Algebra Difficulty 2.3 Junior Find the answer Canada

A positive number is increased by 60%60\%. By what percentage should the
result be decreased to return to the original value?

Pick one

Solution

Solution 1

Suppose that the original number is 100.

When 100 is increased by 60%, the result is 160.

To return to the original value of 100, 160 must be decreased by
60.

This percentage is $60160×\$\frac{60}{160} \times
100\% = 38×\frac{3}{8} \times 100\% = 37.5\%$.

Solution 2

Suppose that the original number is xx for some $x
> 0$.

When xx is increased by 60%, the
result is 1.6x1.6x.

To return to the original value of xx, 1.6x1.6x must be decreased by 0.6x0.6x.

This percentage is $0.6x1.6x×\$\frac{0.6x}{1.6x} \times
100\% = 38×\frac{3}{8} \times 100\% = 37.5\%$.

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Source: CEMC, University of Waterloo, licensed CC-BY-NC-4.0. Statement reproduced verbatim; metadata (topic, difficulty) added by this project.