Maths Olympiad Prep

Library / /31 of 387

, 2008

Algebra Difficulty 1.0 Junior Find the answer Canada

If 40x1=19\dfrac{40}{x} - 1 = 19, then xx is equal to

(A) 1-1 (B) 12\frac{1}{2} (C) 11 (D) 22 (E) 2-2

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Source: CEMC, University of Waterloo, licensed CC-BY-NC-4.0. Statement reproduced verbatim; metadata (topic, difficulty) added by this project. Solutions are the publisher's, linked not copied.