Maths Olympiad Prep

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CEMC Cayley, 2021

Algebra Difficulty 1.4 Junior Find the answer Canada

If x=2x=2 and y=x2−5y=x^2-5 and z=y2−5z=y^2-5, then zz equals

Pick one

Solution

Since x=2x=2 and y=x2−5y = x^2 - 5, then y=22−5=4−5=−1y = 2^2 - 5 = 4 - 5 = -1.

Since y=−1y=-1 and z=y2−5z = y^2 - 5, then z=(−1)2−5=1−5=−4z = (-1)^2 - 5 = 1 - 5 = -4.

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