Maths Olympiad Prep

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, 2011

Algebra Difficulty 3.0 AMC 10/12 Find the answer Canada

Suppose that xx and yy are positive numbers with xy=19xy = \frac{1}{9}, x(y+1)=79x(y+1) = \frac{7}{9}, y(x+1)=518y(x+1) = \frac{5}{18}. What is the value of (x+1)(y+1)(x+1)(y+1)?

(A) 116\frac{11}{6} (B) 89\frac{8}{9} (C) 169\frac{16}{9} (D) 109\frac{10}{9} (E) 3518\frac{35}{18}

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