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CEMC Fermat, 2012

Geometry Difficulty 2.1 Junior Find the answer Canada

In the diagram, HF=HGHF=HG and JFGJFG is a straight line segment. The value of xx is

Figure 0

A number or a short expression. Fractions can be typed as 3/2, and spacing doesn't matter.

Solution

Since JFGJFG is a straight line, then ∠HFG=180∘−∠HFJ=180∘−110∘=70∘\angle HFG = 180^\circ - \angle HFJ = 180^\circ - 110^\circ = 70^\circ.

Since △FGH\triangle FGH is isosceles with HF=HGHF = HG, then ∠HGF=∠HFG=70∘\angle HGF = \angle HFG = 70^\circ.

Since the sum of the angles in △FGH\triangle FGH is 180∘180^\circ, then 70∘+70∘+x∘=180∘70^\circ + 70^\circ + x^\circ = 180^\circ, and so 140+x=180140+x = 180 or x=40x=40.

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