Maths Olympiad Prep

Library / /40 of 356

, 2005

Algebra Difficulty 1.0 Junior Find the answer Canada

The symbol 3456\begin{array}{|c|c|}\hline 3 & 4 \\ \hline 5 & 6 \\ \hline \end{array} is evaluated as 3×6+4×5=383 \times 6 + 4 \times 5 = 38. If 261\begin{array}{|c|c|}\hline 2 & 6 \\ \hline 1 & \square \\ \hline \end{array} is evaluated as 1616, then the number that should be placed in the empty space is

(A) 11 (B) 22 (C) 33 (D) 44 (E) 55

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