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CEMC Fermat, 2021

Algebra Difficulty 1.2 Junior Find the answer Canada

For which of the following values of xx is xx greater than x2x^2 ?

x=−2x=-2
x=−12x=-\frac{1}{2}
x=0x=0
x=12x=\frac{1}{2}
x=2x=2

A number or a short expression. Fractions can be typed as 3/2, and spacing doesn't matter.

Solution

When x=−2x=-2, we get x2=4x^2 = 4. Here, x lt; x 2\text{x lt; x 2}.

When x=−12x=-\frac{1}{2}, we get x2=14x^2 = \frac{1}{4}. Here, x lt; x 2\text{x lt; x 2}.

When x=0x=0, we get x2=0x^2=0. Here, x=x2x=x^2.

When x=12x=\frac{1}{2}, we get x2=14x^2 = \frac{1}{4}. Here, x gt; x 2\text{x gt; x 2}.

When x=2x=2, we get x2=4x^2 = 4. Here, x lt; x 2\text{x lt; x 2}.

This means that x=12x=\frac{1}{2} is the only choice where x gt;x 2\text{x gt;x 2}.

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