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CEMC Fermat, 2022

Algebra Difficulty 1.2 Junior Find the answer Canada

The expression (1+2+3)(1+12+13)(1+2+3)(1+\frac{1}{2}+\frac{1}{3}) is
equal to

Pick one

Solution

Evaluating, (1+2+3)(1+12+13)=6(1+12+13)=6+62+63=6+3+2=11(1+2+3)(1 + \frac{1}{2} + \frac{1}{3}) = 6(1 + \frac{1}{2} + \frac{1}{3}) = 6 + \frac{6}{2} + \frac{6}{3} = 6 + 3 + 2 = 11.

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Source: CEMC, University of Waterloo, licensed CC-BY-NC-4.0. Statement reproduced verbatim; metadata (topic, difficulty) added by this project.