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, 2022 Algebra Difficulty 1.2 Junior Find the answer Canada
The expression ( 1 + 2 + 3 ) ( 1 + 1 2 + 1 3 ) (1+2+3)(1+\frac{1}{2}+\frac{1}{3}) ( 1 + 2 + 3 ) ( 1 + 2 1 + 3 1 ) is equal to
Pick one
A 3 3 3 B 11 11 11 C 6 6 6 D 11 6 \dfrac{11}{6} 6 11 E 12 12 12
Solution Evaluating, $(1+2+3)(1 + 1 2 + 1 3 ) \frac{1}{2} +
\frac{1}{3}) 2 1 + 3 1 ) = 6(1 + 1 2 + 1 3 ) \frac{1}{2} + \frac{1}{3}) 2 1 + 3 1 ) = 6 + 6 2 + 6 3 \frac{6}{2} +
\frac{6}{3} 2 6 + 3 6 = 6 + 3 + 2 = 11$.
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