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Algebra Difficulty 1.3 Junior Find the answer Canada

Suppose that $6x + 3 = y$ ,
where $x$ is a positive integer. A
possible value of $y$ is

Pick one

Solution

Since $x$ is a positive
integer and $y=6x+3$ , then $y$ is 3 more than a positive multiple of
$6$ . Since $45=6\times7+3$ , then $y=45$ when $x=7$ . Of the given answers, $45$ is the only number that is $3$ more than a positive multiple of $6$ .

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Source: CEMC, University of Waterloo, licensed CC-BY-NC-4.0. Statement reproduced verbatim; metadata (topic, difficulty) added by this project.