Maths Olympiad Prep

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CEMC Cayley, 2021

Algebra Difficulty 1.6 Junior Find the answer Canada

If 3x=53^{x}=5, the value of 3x+23^{x+2} is

Pick one

Solution

Using exponent laws, 3x+2=3x⋅32=3x⋅93^{x+2} = 3^x \cdot 3^2 = 3^x \cdot 9.

Since 3x=53^x=5, then 3x+2=3x⋅9=5⋅9=453^{x+2} = 3^x \cdot 9 = 5 \cdot 9 = 45.

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