Maths Olympiad Prep

Library / /45 of 387

, 2003

Algebra Difficulty 1.0 Junior Find the answer Canada

If 1x+15=53\dfrac{1}{x+\frac{1}{5}} = \dfrac{5}{3}, then xx equals

(A) 25\dfrac{2}{5} (B) 45\dfrac{4}{5} (C) 15\dfrac{1}{5} (D) 25-\dfrac{2}{5} (E) 225-\dfrac{22}{5}

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Source: CEMC, University of Waterloo, licensed CC-BY-NC-4.0. Statement reproduced verbatim; metadata (topic, difficulty) added by this project. Solutions are the publisher's, linked not copied.