Library / /222 of 387

, 2003

Algebra Difficulty 2.0 Junior Find the answer Canada

The value of $\dfrac{(4^{2003})(3^{2002})}{(6^{2002})(2^{2003})}$ is

(A) $1$ (B) $2$ (C) $12$ (D) $4$ (E) $\dfrac{1}{2}$

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Source: CEMC, University of Waterloo, licensed CC-BY-NC-4.0. Statement reproduced verbatim; metadata (topic, difficulty) added by this project. Solutions are the publisher's, linked not copied.