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In the diagram, HF=HGHF=HGHF=HG and JFGJFGJFG is a straight line segment. The value of xxx is
A number or a short expression. Fractions can be typed as 3/2, and spacing doesn't matter.
Since JFGJFGJFG is a straight line, then ∠HFG=180∘−∠HFJ=180∘−110∘=70∘\angle HFG = 180^\circ - \angle HFJ = 180^\circ - 110^\circ = 70^\circ∠HFG=180∘−∠HFJ=180∘−110∘=70∘.
Since △FGH\triangle FGH△FGH is isosceles with HF=HGHF = HGHF=HG, then ∠HGF=∠HFG=70∘\angle HGF = \angle HFG = 70^\circ∠HGF=∠HFG=70∘.
Since the sum of the angles in △FGH\triangle FGH△FGH is 180∘180^\circ180∘, then 70∘+70∘+x∘=180∘70^\circ + 70^\circ + x^\circ = 180^\circ70∘+70∘+x∘=180∘, and so 140+x=180140+x = 180140+x=180 or x=40x=40x=40.
Source: CEMC, University of Waterloo, licensed CC-BY-NC-4.0. Statement reproduced verbatim; metadata (topic, difficulty) added by this project.