Maths Olympiad Prep

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Algebra Difficulty 3.7 AMC 10/12 Find the answer Canada

The function ff has the properties that f(1)=6f(1) =6 and f(2x+1)=3f(x)f(2x+1)=3f(x) for every integer xx. What is the value of f(63)f(63)?

Pick one

Solution

We use the functional equation f(2x+1)=3f(x)f(2x+1)=3f(x) repeatedly.

Setting x=1x=1, we get f(3)=3f(1)=3×6=18f(3) = 3f(1) = 3 \times 6 = 18.

Setting x=3x=3, we get f(7)=3f(3)=3×18=54f(7) = 3f(3) = 3 \times 18 =54.

Setting x=7x=7, we get f(15)=3f(7)=3×54=162f(15) = 3f(7) = 3 \times 54 =162.

Setting x=15x=15, we get f(31)=3f(15)=3×162=486f(31) = 3f(15) = 3 \times 162 =486.

Setting x=31x=31, we get f(63)=3f(31)=3×486=1458f(63) = 3f(31) = 3 \times 486 =1458.

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Source: CEMC, University of Waterloo, licensed CC-BY-NC-4.0. Statement reproduced verbatim; metadata (topic, difficulty) added by this project.