GeometryDifficulty 3.5AMC 10/12Find the answerCanada
The diameters PQ, RS and TU of three identical semi-circles are placed along line PU, as shown.
If PR=SU=8 and QT=5, then the length of PQ is
Pick one
Solution
Suppose the diameter of each semi-circle is x.
That is, PQ=RS=TU=x, and so PU=PQ+QT+TU=x+5+x=2x+5.
Also, PU=PR+RS+SU=8+x+8=x+16.
Thus, 2x+5=x+16 or x=11, and so PQ=11.
Want a route through all this instead of an archive? The track
puts 2,604 problems in a working order, from Junior Challenge level to the IMO shortlist.