GeometryDifficulty 3.5AMC 10/12Find the answerCanada
The diameters PQ, RS and TU of three identical semi-circles are placed along line PU, as shown.If PR=SU=8 and QT=5, then the length of PQ is
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Solution
Suppose the diameter of each semi-circle is x. That is, PQ=RS=TU=x, and so PU=PQ+QT+TU=x+5+x=2x+5. Also, PU=PR+RS+SU=8+x+8=x+16. Thus, 2x+5=x+16 or x=11, and so PQ=11.
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