Maths Olympiad Prep

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CEMC Cayley, 2023

Geometry Difficulty 2.2 Junior Find the answer Canada

In the diagram, points BB,
CC and DD lie on a line. Also, ∠ABC=90°\angle ABC = 90\degree and ∠ACD=150°\angle ACD = 150\degree.

Figure 0

The value of xx is

Pick one

Solution

Solution 1

Since ∠BCD\angle BCD is a straight
angle, then ∠ACB=180°−∠ACD=180°−150°=30°\angle ACB = 180\degree - \angle ACD = 180\degree - 150\degree = 30\degree.

Since the measures of the angles in △ABC\triangle ABC add to 180°180\degree, then x°+90°+30°=180°x\degree + 90\degree + 30\degree = 180\degree and so x=180−120=60x = 180 - 120 = 60.

Solution 2

Since the measures of the angles in △ABC\triangle ABC add to 180°180\degree, then ∠ACB=180°−∠ABC−∠BAC=180°−90°−x°=90°−x°\angle ACB = 180\degree - \angle ABC - \angle BAC = 180\degree - 90\degree - x\degree = 90\degree - x\degree
Since ∠BCD=180°\angle BCD = 180\degree, then
∠ACB+∠ACDamp;=180°(90°−x°)+150°amp;=180°240−xamp;=180\begin{align*} \angle ACB + \angle ACD & = 180\degree \\ (90\degree - x\degree) + 150\degree & = 180\degree \\ 240 - x & = 180\end{align*} and so x=60x = 60.

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