CEMC Cayley, 2007

Geometry Difficulty 3.0 AMC 10/12 Find the answer Canada

In the diagram, $\triangle ABC$ is right-angled at $C$ . Also, points $M$ , $N$ and $P$ are the midpoints of sides $BC$ , $AC$ and $AB$ , respectively. If the area of $\triangle APN$ is $2$ cm $^2$ , then the area of $\triangle ABC$ is

(A) $8$ cm $^2$ (B) $16$ cm $^2$ (C) $6$ cm $^2$ (D) $4$ cm $^2$ (E) $12$ cm $^2$

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