Maths Olympiad Prep

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Geometry Difficulty 4.0 AIME Find the answer United States

Problem:

Charlie folds an 172\frac{17}{2}-inch by 1111-inch piece of paper in half twice, each time along a straight line parallel to one of the paper's edges. What is the smallest possible perimeter of the piece after two such folds?

A number or a short expression. Fractions can be typed as 3/2, and spacing doesn't matter.

Solution

Solution:

392\boxed{\frac{39}{2}}

Note that when a piece of paper is folded in half, one pair of opposite sides is preserved and the other pair is halved. Hence, the net effect on the perimeter is to decrease it by one of the side lengths. The original perimeter is 2(172)+211=392\left(\frac{17}{2}\right) + 2 \cdot 11 = 39. By considering the cases of folding twice along one edge or folding once along each edge, one can see that this perimeter can be decreased by at most 11+172=39211 + \frac{17}{2} = \frac{39}{2}. Hence, the minimal perimeter is 392\frac{39}{2}.

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Source: MathNet, licensed CC-BY-4.0. Statement reproduced verbatim; metadata (topic, difficulty) added by this project.