Maths Olympiad Prep

Library / /1 of 82

Algebra Difficulty 3.9 AMC 10/12 Find the answer United States

Problem:

Let xx be a real number such that 2x=32^{x} = 3. Determine the value of 43x+24^{3x+2}.

A number or a short expression. Fractions can be typed as 3/2, and spacing doesn't matter.

Solution

Solution:

We have
43x+2=43x42=(22)3x16=26x16=(2x)616=3616=11664 4^{3x+2} = 4^{3x} \cdot 4^{2} = \left(2^{2}\right)^{3x} \cdot 16 = 2^{6x} \cdot 16 = \left(2^{x}\right)^{6} \cdot 16 = 3^{6} \cdot 16 = 11664

Want a route through all this instead of an archive? The track puts 2,000 problems in a working order, from AMC 10 level to the IMO shortlist.

Source: MathNet, licensed CC-BY-4.0. Statement reproduced verbatim; metadata (topic, difficulty) added by this project.