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HMMT February Guts Round, 2024

Number theory Difficulty 4.7 AIME Prove it United States

Problem:

Compute the sum of all integers nn such that n2−3000n^{2}-3000 is a perfect square.

Solution

Solution:

If n2−3000n^{2}-3000 is a square, then (−n)2−3000(-n)^{2}-3000 is also a square, so the sum is 0.

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Source: MathNet, licensed CC-BY-4.0. Statement reproduced verbatim; metadata (topic, difficulty) added by this project.