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HMMT February Guts Round, 2024

Number theory Difficulty 4.6 AIME Find the answer United States

Problem:
Let a⋆b=ab−2a \star b = a b - 2. Compute the remainder when (((579⋆569)⋆559)⋆⋯⋆19)⋆9(((579 \star 569) \star 559) \star \cdots \star 19) \star 9 is divided by 100100.

A number or a short expression. Fractions can be typed as 3/2, and spacing doesn't matter.

Solution

Solution:
Note that
(10a+9)⋆(10b+9)=(100ab+90a+90b+81)−2≡90(a+b)+79(mod100) (10 a + 9) \star (10 b + 9) = (100 a b + 90 a + 90 b + 81) - 2 \equiv 90(a + b) + 79 \pmod{100}
so throughout our process all numbers will end in 99, so we will just track the tens digit. Then the "new operation" is
a†b≡−(a+b)+7(mod10) a \dagger b \equiv -(a + b) + 7 \pmod{10}
where aa and bb track the tens digits. Now
(a†b)†c≡(−(a+b)+7)†c≡a+b−c(mod10). (a \dagger b) \dagger c \equiv (-(a + b) + 7) \dagger c \equiv a + b - c \pmod{10}.
Thus, our expression has tens digit congruent to
−0+1−2+3−⋯−54+55−56−57+7≡−28−57+7≡2(mod10) -0 + 1 - 2 + 3 - \cdots - 54 + 55 - 56 - 57 + 7 \equiv -28 - 57 + 7 \equiv 2 \pmod{10}
making the answer 2929.

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