Maths Olympiad Prep

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, 2015

Geometry Difficulty 4.7 AIME Prove it United States

Problem:
Let ABCABC be an acute triangle with orthocenter HH. Let D,ED, E be the feet of the AA-, BB-altitudes respectively. Given that AH=20AH = 20 and HD=15HD = 15 and BE=56BE = 56, find the length of BHBH.

Solution

Solution:
Let xx be the length of BHBH. Note that quadrilateral ABDEABDE is cyclic, so by Power of a Point, x(56x)=2015=300x(56 - x) = 20 \cdot 15 = 300. Solving for xx, we get x=50x = 50 or 66. We must have BH>HDBH > HD so x=50x = 50 is the correct length.

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