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Geometry Difficulty 3.5 AMC 10/12 Find the answer China

In ellipse Γ\Gamma, AA is an endpoint of the major axis, BB is an endpoint of the minor axis, and F1,F2F_1, F_2 are the foci. If AF1AF2+BF1BF2=0\overrightarrow{AF_1} \cdot \overrightarrow{AF_2} + \overrightarrow{BF_1} \cdot \overrightarrow{BF_2} = 0, then the value of ABF1F2\frac{|AB|}{|F_1F_2|} is ______.

A number or a short expression. Fractions can be typed as 3/2, and spacing doesn't matter.

Solution

Without loss of generality, suppose the equation of Γ\Gamma is x2a2+y2b2=1\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1 (a>b>0a > b > 0), and A(a,0)A(a, 0), B(0,b)B(0, b), F1(c,0)F_1(-c, 0), F2(c,0)F_2(c, 0). By the given conditions, we get
AF1AF2+BF1BF2=(ca)(ca)+(c2+b2)=a2+b22c2=0. \overrightarrow{AF_1} \cdot \overrightarrow{AF_2} + \overrightarrow{BF_1} \cdot \overrightarrow{BF_2} = (-c-a)(c-a) + (-c^2+b^2) = a^2+b^2-2c^2 = 0.
Therefore, ABF1F2=a2+b22c=2c22c=22\frac{|AB|}{|F_1F_2|} = \frac{\sqrt{a^2+b^2}}{2c} = \frac{\sqrt{2c^2}}{2c} = \frac{\sqrt{2}}{2}. \square

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