Maths Olympiad Prep

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, 2023

Combinatorics Difficulty 4.9 AIME Find the answer United States

Problem:
The Fibonacci numbers are defined recursively by F0=0F_{0}=0, F1=1F_{1}=1, and Fi=Fi1+Fi2F_{i}=F_{i-1}+F_{i-2} for i2i \geq 2. Given 15 wooden blocks of weights F2,F3,,F16F_{2}, F_{3}, \ldots, F_{16}, compute the number of ways to paint each block either red or blue such that the total weight of the red blocks equals the total weight of the blue blocks.

A number or a short expression. Fractions can be typed as 3/2, and spacing doesn't matter.

Solution

Solution:
Partition the blocks into sets
{F2,F3,F4},{F5,F6,F7},,{F14,F15,F16} \left\{F_{2}, F_{3}, F_{4}\right\},\left\{F_{5}, F_{6}, F_{7}\right\}, \ldots,\left\{F_{14}, F_{15}, F_{16}\right\}
We can show by bounding that F16F_{16} belongs on the opposite side as F15F_{15} and F14F_{14}, and, in general, that F3k+1F_{3k+1} is on the opposite side as F3kF_{3k} and F3k1F_{3k-1}. Hence, it suffices to choose which side each of F4,F7,,F16F_{4}, F_{7}, \ldots, F_{16} go. This gives 25=322^{5}=32 ways.

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Source: MathNet, licensed CC-BY-4.0. Statement reproduced verbatim; metadata (topic, difficulty) added by this project.