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HMMT November, 2018

Geometry Difficulty 4.8 AIME Prove it United States

Problem:

HOWH O W, BOWB O W, and DAHD A H are equilateral triangles in a plane such that WO=7W O = 7 and AH=2A H = 2. Given that DD, AA, BB are collinear in that order, find the length of BAB A.

Solution

Solution:

Note that H≠BH \neq B since otherwise DABD A B is an equilateral triangle. Let MM be the midpoint of DAD A, so HB=73H B = 7 \sqrt{3} and HM=3H M = \sqrt{3}, and ∠HMB=90∘\angle H M B = 90^{\circ}. By the Pythagorean theorem,
BM=(73)2−(3)2=12 B M = \sqrt{(7 \sqrt{3})^2 - (\sqrt{3})^2} = 12
Then BA=BM−AM=11B A = B M - A M = 11.

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