HOW, BOW, and DAH are equilateral triangles in a plane such that WO=7 and AH=2. Given that D, A, B are collinear in that order, find the length of BA.
Solution
Solution:
Note that H=B since otherwise DAB is an equilateral triangle. Let M be the midpoint of DA, so HB=73 and HM=3, and ∠HMB=90∘. By the Pythagorean theorem, BM=(73)2−(3)2=12 Then BA=BM−AM=11.
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