Maths Olympiad Prep

Library / /6 of 6

Combinatorics Difficulty 5.7 AIME, harder Prove it United States

Problem:

The lottery cards of a certain lottery contain all nine-digit numbers that can be formed with the digits 11, 22 and 33. There is exactly one number on each lottery card. There are only red, yellow and blue lottery cards. Two lottery numbers that differ from each other in all nine digits always appear on cards of different color. Someone draws a red card and a yellow card. The red card has the number 122222222122222222 and the yellow card has the number 222222222222222222. The first prize goes to the lottery card with the number 123123123123123123. What color(s) can it possibly have? Prove your answer.

Solution

Solution:

First, it can in fact be red, if, say, cards are colored based on the first digit only (1=1= red, 2=2= yellow, 3=3= blue)). We now endeavor to show it must be red.

Consider the cards 333133133333133133 and 331331331331331331: they each differ in all their digits from 122222222122222222 and from 222222222222222222, so they must both be blue. Now 211311311211311311 differs in all its digits from both 122222222122222222 and 333133133333133133, so it must be yellow. Finally, 123123123123123123 differs in all its digits from both 331331331331331331 and 211311311211311311, so it must be red.

Want a route through all this instead of an archive? The track puts 2,000 problems in a working order, from AMC 10 level to the IMO shortlist.

Source: MathNet, licensed CC-BY-4.0. Statement reproduced verbatim; metadata (topic, difficulty) added by this project.