Let x0,x1,x2,… be the sequence defined by x0=2 and xn+1=5+(xn)2 for every n≥0. Prove that this sequence does not contain any prime numbers other than 2.
Solution
Solution:
Note that the numbers in question are alternately even and odd, because 5 is added to the square of the previous term. Therefore only the terms in odd position can give other primes. But these are all multiples of 3 and greater than or equal to x1=9. Indeed the sequence is clearly increasing, and in passing from xn to xn+2=5+(5+xn)2=30+10(xn)2+(xn)4 divisibility by 3 is preserved.
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