Maths Olympiad Prep

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, 2003

Algebra Difficulty 4.6 AIME Prove it Italy

Problem:

Let x0,x1,x2,x_{0}, x_{1}, x_{2}, \ldots be the sequence defined by x0=2x_{0}=2 and xn+1=5+(xn)2x_{n+1}=5+\left(x_{n}\right)^{2} for every n0n \geq 0. Prove that this sequence does not contain any prime numbers other than 2.

Solution

Solution:

Note that the numbers in question are alternately even and odd, because 55 is added to the square of the previous term. Therefore only the terms in odd position can give other primes. But these are all multiples of 33 and greater than or equal to x1=9x_{1}=9. Indeed the sequence is clearly increasing, and in passing from xnx_{n} to xn+2=5+(5+xn)2=30+10(xn)2+(xn)4x_{n+2}=5+\left(5+x_{n}\right)^{2}=30+10\left(x_{n}\right)^{2}+\left(x_{n}\right)^{4} divisibility by 33 is preserved.

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Source: MathNet, licensed CC-BY-4.0. Statement translated into English from it; metadata (topic, difficulty) added by this project.