Let ABC be a triangle with circumradius R=17 and inradius r=7. Find the maximum possible value of sin2A.
Solution
Solution:
Letting I and O denote the incenter and circumcenter of triangle ABC we have by the triangle inequality that AO≤AI+OI⟹R≤sin2Ar+R(R−2r) and by plugging in our values for r and R we get sin2A≤3417+51 as desired. Equality holds when ABC is isosceles and I lies between A and O.
Want a route through all this instead of an archive? The track
puts 2,000 problems in a working order, from AMC 10 level to the IMO shortlist.
Source: MathNet,
licensed CC-BY-4.0.
Statement reproduced verbatim; metadata (topic, difficulty) added by this project.