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Belarus — Selection and Training Session

Geometry Difficulty 5.5 AIME, harder Prove it Belarus

Point LL is marked on the side ABAB of a triangle ABCABC. The incircle of the triangle ABCABC meets the segment CLCL at points PP and QQ.
Is it possible that the equalities CP=PQ=QLCP = PQ = QL hold if CLCL is

a) the median?
b) the bisector?
c) the altitude?
d) the segment joining vertex CC with the point LL of tangency of the excircle of the triangle ABCABC with ABAB?

Solution

a) yes, it is possible; this is valid for the triangles with AC=5xAC = 5x, AB=10xAB = 10x, BC=13xBC = 13x, where xx is any positive real number;

b) it is impossible;

c) it is impossible;

d) yes, it is possible; this is valid for the triangles with AC=3xAC = 3x, AB=4xAB = 4x, BC=5xBC = 5x, where xx is any positive real number.

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Source: MathNet, licensed CC-BY-4.0. Statement reproduced verbatim; metadata (topic, difficulty) added by this project.