Let ABC be a right triangle at A, with ∠ABC=15∘. Let H be the foot of the altitude from A and let J,K be the projections of H onto AB and onto AC. Knowing that the area of AJHK is 45cm2, how many cm2 is the product BJ⋅CK?
Solution
Solution:
The answer is 45. Setting x=AJ, y=AK, x′=JB and y′=KC, using the second Euclid's theorem we have x⋅x′=y2 and y⋅y′=x2. Multiplying side by side we get (x⋅x′)(y⋅y′)=(x′⋅y′)(x⋅y)=x2⋅y2, from which x′⋅y′=x⋅y=45.
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Source: MathNet,
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