Maths Olympiad Prep

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Geometry Difficulty 4.6 AIME Prove it Italy

Problem:

Let ABCABC be a right triangle at AA, with ABC=15\angle ABC = 15^\circ. Let HH be the foot of the altitude from AA and let J,KJ, K be the projections of HH onto ABAB and onto ACAC. Knowing that the area of AJHKAJHK is 45 cm245~\mathrm{cm}^2, how many cm2\mathrm{cm}^2 is the product BJCKBJ \cdot CK?

Solution

Solution:

The answer is 4545. Setting x=AJx = AJ, y=AKy = AK, x=JBx' = JB and y=KCy' = KC, using the second Euclid's theorem we have xx=y2x \cdot x' = y^2 and yy=x2y \cdot y' = x^2. Multiplying side by side we get (xx)(yy)=(xy)(xy)=x2y2\left(x \cdot x'\right)\left(y \cdot y'\right) = \left(x' \cdot y'\right)(x \cdot y) = x^2 \cdot y^2, from which xy=xy=45x' \cdot y' = x \cdot y = 45.

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Source: MathNet, licensed CC-BY-4.0. Statement translated into English from it; metadata (topic, difficulty) added by this project.