Maths Olympiad Prep

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, 2021

Geometry Difficulty 4.9 AIME Prove it United States

Problem:

Triangle ABCA B C has a right angle at CC, and DD is the foot of the altitude from CC to ABA B. Points LL, MM, and NN are the midpoints of segments ADA D, DCD C, and CAC A, respectively. If CL=7C L = 7 and BM=12B M = 12, compute BN2B N^{2}.

Solution

Solution:

Note that CLC L, BMB M, and BNB N are corresponding segments in the similar triangles ACDCBDABC\triangle A C D \sim \triangle C B D \sim \triangle A B C. So, we have
CL:BM:BN=AD:CD:AC C L : B M : B N = A D : C D : A C
Since AD2+CD2=AC2A D^{2} + C D^{2} = A C^{2}, we also have CL2+BM2=BN2C L^{2} + B M^{2} = B N^{2}, giving an answer of 49+144=19349 + 144 = 193.

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