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Austria competition problems, 2010

Combinatorics Difficulty 5.7 AIME, harder Prove it Austria

We are given the set Mn={0,1,2,...,n}M_n = \{0, 1, 2, ..., n\} of all non-negative integers less than or equal to nn. We call a subset SS of MnM_n outstanding if it is not empty and a kk-element subset of SS exists for all k∈Sk \in S. Determine the number of outstanding subsets of MnM_n.

Solution

If kk is the largest element of an outstanding subset SS, it follows that SS must contain kk elements. This is possible if it either contains all elements not greater than kk or all but one. We see that each outstanding subset of MnM_n corresponds to an ordered pair (a,b)(a, b) of integers with n≥a≥b≥0n \ge a \ge b \ge 0, whereby the case of an a+1a+1 element subset with maximum element aa is denoted by the pair (a,a)(a, a) and an aa element subset with maximum element aa and missing the number bb is denoted by (a,b)(a, b). We also note that each such pair corresponds directly to an outstanding subset. The number of outstanding subsets is therefore equal to the number of ordered pairs of this type. This number is equal to the number of 2-element subsets of MnM_n plus the number of elements of MnM_n. We see that the number of outstanding subsets is equal to
(n+12)+(n+1)=(n+22) \binom{n+1}{2} + (n+1) = \binom{n+2}{2}

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