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Geometry Difficulty 4.9 AIME Prove it Austria

In the isosceles triangle ABCABC with AC=BC\overline{AC} = \overline{BC} we denote by DD the foot of the altitude through CC. The midpoint of CDCD is denoted by MM. The line BMBM intersects ACAC in EE. Prove that the length of ACAC is three times that of CECE.

Figure 1
Figure 4: Problem 16

Solution

We consider the centroid SS of triangle DBCDBC, which lies on the axis BMBM; see Figure 4. The centroidal axis DSDS bisects the segment BCBC, thus DSDS is parallel to ACAC by the intercept theorem. Since the centroid divides the centroidal axis in the ratio 2:12 : 1, we have the same division ratio on the parallel line ACAC, i.e. EE divides ACAC in the ratio 2:12 : 1.

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